Re: accelerate seven (or more) substitute

> I am doing this job for each line of a 4000 lines files :
>
> let l:lineArranged = substitute(l:lineArranged, 'foo1', 'BAR1', "")
> let l:lineArranged = substitute(l:lineArranged, 'foo2', 'BAR2', "")
> ...
> ..
> let l:lineArranged = substitute(l:lineArranged, 'foo7', 'BAR7', "")

Can an item appear more than once (for which you only want to replace
the first match), or is it okay to use the "g" flag?

If you can do all of them, I'd just use (check for levels of escaping,
as I'm not sure the "\ze" should be "\\ze"...it's untested, but close
enough to get you the idea)

substitute(l:lineArranged, 'foo\ze[1-7]', 'bar', 'g')

I see you're still trying to do this with variables rather than dealing
with lines in a buffer -- you'll find Vim affords many more conveniences
for working with lines-in-buffers than it does for manipulating
variables. So I'll continue to urge you to consider changing your
methodology, even if you continue to disregard it :)

-tim

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