Re: Patterns, variables and strange behavior of some thing.

jojahti wrote:
> I have tried write highligting pattern, than search variables.
> "\(\(int\|long\|short\|char\|void\|double\)[[:space:]]\+\)\@<=[^[:space:]^(^).]\+\([[:space:]]\)\@
> ="
>
> Then the pattern, that search this variable in other places of the file.
> "\(\(int\|long\|short\|char\|void\|double\)\([[:space:]]\+\)\([^[:space:]^(^).]\+\)[[:sp
> ace:]].*\)\@<=\4"
> But fail.
>
> I see, that this thing have very strange behavior.
> I have made little experiment/
> I make this string:
> oo ib b oooooooooo
>
> And try serch in it, using this pattern:
> '\(i\(.\)[[:space:]]*\)\@<=/2'
> And now i have fail.
> But if i cut '\@<=' - then all work normal.
> But I need to use these things.

Jojahti,
There's a better way to do what you're trying to do, which uses \zs
instead of \@<=.

:help \zs

As Ben Fritz pointed out, the pattern within...
\( ... \)\@<=
...is tried only *after* the actual pattern is matched; i.e., too late
for the submatches contained by the lookbehind to be used in the actual
pattern. But what if you changed the pattern above to the following?

\(i\(.\)[[:space:]]*\)\zs\2

The \zs ensures that the match begins at the character matched by \2;
the difference between this and the original pattern is that the portion
of the pattern before the \zs is tried *first* (as it really must be if
the \2 backreference is to be useful).

Out of curiosity, what are you trying to match with [^[:space:]^(^).]?

Thanks,
Brett Stahlman

>
> Why behavior of it is so strange? How to me complete my quest the most
> adequate way?

>
> P.S. it's my first post in English. :thinking:
> Forums on my native language, where I can ask this question - about zero.
>
>

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