> I'm trying do replace strings that contain return characters.
> I tried many things, as:
>
> :g/\n0\n/s//\n1\n/g
> :g/\n0\n/s//\r1\r/g
> (and all combinations of \r and \n possible)
Your 2nd one is the closest -- for some reason (likely backwards
compatibility, but it's always bugged me just a little),
*searching* looks for "\n" as a newline, but replacements use
"\r". I think what you want is
:%s/^0\n0$/1\r1/
In this regexp, the "g" flag is superfluous because you're
anchoring to the start and end of the line, so you'll only find
one match.
-tim
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