Re: Replacements with return

On 22 maio, 19:59, Gary Johnson <garyj...@spocom.com> wrote:
> On 2010-05-22,leandromartinez98wrote:
> > I'm trying do replace strings that contain return characters. For
> > example,
> > I would like to change:
>
> > ----
>
> > 0
> > 0
> > ----
>
> > to
>
> > ----
>
> > 1
> > 1
>
> > ---
>
> > I tried many things, as:
>
> > :g/\n0\n/s//\n1\n/g
> > :g/\n0\n/s//\r1\r/g
> > (and all combinations of \r and \n possible)
> > and variations of that using ^V+Return, ^V+^M.
>
> > None of the combinations above give the correct result. For
> > instance, :g/\n0\n/s//\n1\n/g results in:
>
> > -----
> > ^@1^@0
> > -----
>
> > And :g/\n0\n/s//\r1\r/g
>
> > results in:
>
> > ----
>
> > 1
> > 0
>
> > ----
>
> > I'm not getting the logic. Is there any symbol which represents
> > the return character uniquely and acts in search/replace as a
> > normal character?
>
> If all you're searching for are strings that are bounded by
> newlines, and not strings that contain newlines, I think you would
> get better results using ^ to anchor the string to the beginning of
> a line and $ to anchor it to the end of a line, like this:
>
>     :%s/^0$/1/
>
> Note that ^ and $ match the beginning and end of the line with zero
> width--they don't match a newline character--so no newlines need to
> be included in the replacement string.
>
> The reason your last example didn't work as you expected was that
> your buffer contained
>
>     \n0\n0\n
>
> and your pattern was
>
>     \n0\n
>
> Your pattern matched the first three characters.  After the
> replacement was made, the search resumed with the next character in
> the buffer, which was the second 0.  The pattern did not consider
> the newline preceding the second 0 because that newline had already
> been consumed by the first match.  That's one reason ^ and $ can be
> more useful than \n for anchoring patterns to the ends of lines.
>
> HTH,
> Gary
>
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Thanks Gary!

:%s/^0$/1/

Was exactly what I was searching for! Thank you all, I didn't know
there
was a search pattern for beginning and end of lines, so that prompted
my search for replacements of the return character.

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