Re: substitute with list content (oops)

On 20/07/11 11:32, Tony Mechelynck wrote:
> On 20/07/11 10:21, Chen San wrote:
>> i have saw some usages in such a form:
>>
>> let i=1 | g/foo/s//\="blah_".i/ | let i=i+1
>>
>> then my question is, what if i wanna substitute something with a list,
>> such as ['one','two','three']
>>
>> i have try the next script:
>>
>> let i=0
>>
>> let alist=['one','two','three']
>>
>> for n in alist
>> g/foo/s//\=n/
>> endfor
>>
>> let i=i+1
>>
>>
>> but all the 'foo' there would be replaced with 'one', not the 'two' or
>> 'three'.
>>
>> anyone have any ideas?
>>
>> thanks.
>
> the problem with
>
> for n in alist
> g/foo/s//\=n/
> endfor
>
> is that you'll set n to 1, scan the whole file replacing foo by the
> value of n (which is 1) then scan the whole file again with n=2, not
> find any foo, etc.
>
> Your first idea is in a better direction: I think that
>
> :let i=1 | g/foo/s//\=i/g|let i+=1
> or
> :let i=1 | exe 'g/foo/s//\=i/g|let i+=1' | unlet i

oops! Forgot that you wanted the i-th item in the list

:let i=0 | g/foo/s//\=alist[i]/g|let i+=1

>
> would work, provided that there are no more occurrences of foo than the
> length of the list. (the :let i+=1 is regarded here as part of the
> argument of the :g command, so it is executed immediately after the
> substitute on every matching line.)
>
> The /g switch assumes that you want to replace every occurrence of
> "foo", even several per line and even in the middle of a word. You can
> of course restrict that by means of the following zero-length pattern
> items:
>
> \< start of word
> \> end of word
> ^ start of line
> $ end of line
>
> Best regards,
> Tony.
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