Re: Searching pattern in vim

Thanks a lot Tony!

On Mon, Feb 6, 2017 at 3:36 PM, Tony Mechelynck <antoine.mechelynck@gmail.com> wrote:

To erase everything until the last slash on every line of the current file:

:%s/.*\//

i.e "replace any number of characters" (dot means "anything except a
line break"), "as many as possible" (that's the star), "ending in a
(backslash-escaped) slash, by nothing". The % range is short for 1,$
i.e. "from first to last line".

If there are several slashes on a line, all of them except the last
one will be caught by the .* part.

To get the part of a string data item after the last slash, you use
the same pattern:

:let result = substitute(givenstring, '.*\/', '', '')

I'm using _single_ quotes, i.e., there are two empty arguments at the
end. 'result' and 'givenstring' are variable-names, you may replace
them by whatever is required at that point in your code.

Best regards,
Tony.

On Mon, Feb 6, 2017 at 10:46 AM, Melvin Simon <whereismelvin@gmail.com> wrote:
> Hi,
>
> Could someone guide me to match patterns in the following manner:-
>
> input
>
> /somealphabets/somethingelse/finalword
>
> output
>
> finalword
>
> i.e. I want to ignore all other'/' and get the last word alone, i.e. word between last / and $ (end of line)
>
> Thanks
>
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