Dmitry Zotikov wrote:
> Dear all,
>
> what would be the best way to silently edit a buffer? In particular, I want to
> be able to write the content of a variable to it, as well as to delete all of
> its content.
>
> The story goes, I'm writing a plugin that among other things reads from a
> network socket using Vim 8 channels and jobs; this is the corresponding call:
>
> call job_start(command_cmd, {'out_io': 'buffer', 'out_name': '_out'})
>
> The problem is that on the other side of the socket there's a server process
> reading from the channel set to NL mode would always leave one line of
> input in the socket, and so I'm forced to either fall back to RAW
> mode, or to check whether there's something left in the socket and
> read it later with a separate ch_read call:
I created a file "temp" that is missing the final EOL.
If I then do:
call job_start("cat temp", {'out_io': 'buffer', 'out_name': '_out'})
Then I see the last line of "temp" in _out.
Thus it appears to work.
Perhaps the server process doesn't flush the output?
> - Writing in RAW mode directly to the buffer leaves ^@ in place of proper
> linefeeds, meaning a callback function would have to be called, that would
> substitute ^@ with ^M and only then write to the buffer; this is where the
> initial question stems from.
> - ch_read() call would also have to be performed by a callback function that
> will, again, need a way to somehow write to the buffer.
>
> The closest solution I've got is to do something like
>
> :bufnr('_out') bufdo put =msg
>
> but that switches the current window to "_out" buffer.
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it so simple that there are obviously no deficiencies. The other way
is to make it so complicated that there are no obvious deficiencies.
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