Re: Replace v:val by v:key in a list if patter matches

Le mercredi 14 février 2018 11:53:11 UTC+1, tyru a écrit :
> Hi Ni Va,
>
> You can choose what you like.
>
> let list = ['foo', 'bar']
> let pattern = 'oo'
>
> echo map(copy(list), 'v:val =~# pattern ? v:key : v:val')
> " or
> echo map(copy(list), 'v:val =~# '.string(pattern).' ? v:key : v:val')
> " or (Vim 8 or higher)
> echo map(copy(list), {i,v -> v =~# pattern ? i : v})
>
> 2018-02-09 3:17 GMT+09:00 Ni Va <nivaemail@gmail.com>:
> > Hi,
> >
> >
> > How can I change list item's value by list index using map(.
> >
> >
> > let list = ['foo', 'bar']
> > let pattern = 'oo'
> > let mappedlist = [0, 'bar']
> >
> > map(copy(s:xml), '(stridx(v:val,'.pattern.')>-1) ? v:key : v:val ')
> >
> >
> > Thank you
> >
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>
>
> --
> Takuya Fujiwara

Thank you very much Takuya Fujiwara !

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