On Thu, 30 Aug 2018 00:20:18 +0100
David Woodfall <dave@dawoodfall.net> wrote:
> On Wednesday 29 August 2018 18:47,
> Lifepillar <lifepillar@lifepillar.me> put forth the proposition:
> > There's a meme (if it may be called so) circulating on Twitter
> > about using Fibonacci sequences for indentation. Just for fun,
> > I wanted to see if it could be implemented using the vartabs
> > feature. I thought that this would do it (for C files):
> >
> > set shiftwidth=0
> > set noexpandtab
>
> Won't this change *all* tab indents to the same size? Surely you need
> to use expandtab?
>
> > set vartabstop=1,1,2,3,5,8,13,21,34
> > set autoindent
> > set smartindent
> > set ft=c
> >
> > With the above settings, it appears that the value of tabstop
> > is used. This seems to agree with shiftwidth's documentation:
> > "When [shiftwidth is] zero the 'ts' value will be used", but
> > not with tabstop's help: "the value of 'tabstop' will be
> > ignored while 'vartabstop' is set". Putting together the two,
> > I would expect the above to use vartabstop.
> >
> > Am I missing something?
>
> I think it may need more work than that, but I may be wrong.
>
> You may need to indentexpr to a custom function and use that
> to set ind.
>
> See :help indentexpr
It looks like someone else saw that twitter post :)
https://github.com/dodie/vim-fibo-indent
Related:
https://github.com/dodie/vim-disapprove-deep-indentation
ಠ_ಠ
-Dave
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