Resolved -- the interloper vi (i.e., what was executed when vi was
called in bash) was a vi that bash had hashed rather than the vi that
was currently in the PATH.
Extract from replies: `which` does not report on what bash will
execute; `type` does. Although `type` provides info on whether the
command is hashed or not, `type -a` does not. `hash -r` clears the hash.
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