Re: How to get the folder from a full file path?

On Tuesday, January 28, 2020 at 1:16:41 AM UTC+8, Gary Johnson wrote:

On 2020-01-27, Zhe Lee wrote:
> I know %:p %:t thes things. But What I need now is not current folder I get a
> full file path from a regex match. 
>
> And now I need to get the folder from this full path. 
>
> I already Google a lot but can't find useful things all related about "%:t :p"
> things so how to make it. 
>
> This is the code I use in the vimrc file. 
>
> function! HandleURL()
>   let s:uri = matchstr(getline("."), '[a-zA-Z]*:\/[^ >,;]*')
>   echo s:uri
>   if s:uri != ""
>     if s:uri =~ '^http'
>         silent exec "AsyncRun chrome ".s:uri.""
>     else
>         """"""""""""""
>         "I want to use the totalcmd64 to run the folder of the s:uri here.
>         """"""""""""""
>         silent exec "AsyncRun TOTALCMD64 ".s:uri.""
>     endif
>   else
>     echo "No URI found in line."
>   endif
> endfunction

I'm not sure I understand.  I think you're looking for fnamemodify()
and the ":h" modifier, perhaps this:

    silent exec "AsyncRun TOTALCMD64 ".fnamemodify(s:uri, ":h")

See

    :help fnamemodify()
    :help filename-modifiers

Regards,
Gary

 

 Thank you. It worked.  But after checking the  manual,  I think  `  silent exec "AsyncRun TOTALCMD64 ".fnamemodify(s:uri, ":p:h") `  It's a better way.  Am I right? 

 Thanks a lot for your help, I already find fnamemodify() before but seems my English is not good enough. 

 

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