On 2020-09-27, Bram Moolenaar <Bram@moolenaar.net> wrote:
>
>> Filter(x, { v -> v =~ '^b' })
>> # E1013
>
> Well, in a sense that is correct. The Filter() functions accepts a
> function reference with a specific type, and what is passed in is a
> function reference without any known type.
Ok, that might be expected, but the above call fails also when
Filter()'s argument is defined simply as `func`, which, according to the
documentation, is the type for arguments that are "any kind of function
reference, no type checking for arguments or return value".
But I'd rather have strict type checking anyway, so what you propose
below would be perfect. Unfortunately, I am not into the implementation
details enough to be helpful. Looking forward to seeing progress in this
area as well!
Life.
> This works:
>
> def Func()
> Filter(x, { v -> v =~ '^b' })
> enddef
> Func()
>
> Because the lambda is compiled.
>
> I suppose what we could do is that when an argument is a lambda, first
> compile it, so that we have the type. This would also make execution
> faster. It gets a bit more complicated if it's a nested structure, e.g.
> dict with a lambda.
>
> --
> A)bort, R)etry, B)ang it with a large hammer
>
> /// Bram Moolenaar -- Bram@Moolenaar.net -- http://www.Moolenaar.net \\\
> /// sponsor Vim, vote for features -- http://www.Vim.org/sponsor/ \\\
> \\\ an exciting new programming language -- http://www.Zimbu.org ///
> \\\ help me help AIDS victims -- http://ICCF-Holland.org ///
>
> --
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