Re: Substitute pattern over multiple lines

On Wed, Dec 23, 2020 at 11:57 PM Tim Chase <vim@tim.thechases.com> wrote:

On 2020-12-23 23:18, John Cordes wrote:
>> :g/^2 TYPE tngnote//2 NOTE /s/^2 NOTE \zs\(.*\n\(\%(\D\|3 CONC
>> \).*\n\)\+\)/\='<div
>> class="xxx">'.substitute(substitute(submatch(1), '\n3 CONC ', '',
>> 'g'), '\n', '', 'g')."<\/div>\n"
>
>  The last ":g..." command I listed above is working correctly
> when there are continuation lines (i.e. at least one "3 CONC" tag
> following the "2 NOTE" tag, but I think it seems to be skipping by
> the "2 NOTE" tags which do *not* have a CONC / Continuation tag.

Ah, while I'm not positive (so shooting from the hip here) I think you
want to change the

  \+

(one or more continuation lines) to just

  *

(zero or more continuation lines) to produce

:g/^2 TYPE tngnote//2 NOTE /s/^2 NOTE \zs\(.*\n\%(\%(\D\|3 CONC
\).*\n\)\+\)/\='<div class="xxx">'.substitute(substitute(submatch(1),
'\n3 CONC ', '', 'g'), '\n', '', 'g')."<\/div>\n"

(I also snuck in an extra "%" in the inner \(…\) which I missed when
transcribing it earlier, but shouldn't impact the results)

-tim

 

 I think that did it - on a quick check.

I had tried changing that "\+" to "\=" thinking that would allow for 0 or 1 but something went wrong - can't remember exactly what right now. I should have just tried * - can't think why I didn't.

 Thanks again!

 John

  

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