> Maybe its easier, to reduce \\ to \ and expand THEN all \ to \\.
>
Oliver's solution is probably easiest, and therefore the best; however,
the following would also do the trick:
:%s/\%(^\|[^\\]\)\zs\\\ze\%([^\\]\|$\)/\\\\/g
Logically, this means:  match a \ so long as:
   * it isn't preceded by a \ (or is at the beginning of line) AND
   * if it isn't followed by a \ (or is at the end of line).
Regards,
Chip Campbell
-- 
You received this message from the "vim_use" maillist.
Do not top-post! Type your reply below the text you are replying to.
For more information, visit http://www.vim.org/maillist.php
No comments:
Post a Comment