Reformat tabular test data ending with a lengthy description onto multiple tabulated lines

   Here is my test data  Example 1     Of medium length     Enough words in description 
to need one reformat  Example 2     Very short one       Needs no reformat  Example 3     Extremely long one   This description is long 
enough and drivels on and on pointlessly for no other purpose 
than to trigger multiple reformatted lines.    Here are the :s commands which produced the best results so far and show exactly what I'm trying to achieve  :'a,'b-1s/.\{66,}/\=substitute(submatch(0),'\(.\{35}\)\(.\{,30}\) \(\(.\{,30}\)[ \n]\)\+','\1\2\r@@\1\3','')/g  :'a,'b-1s/^@@\(.\{35}\)/\=substitute(submatch(1),'.',' ','g')  Here is what they do to my test data  Example 1     Of medium length     Enough words in description to                                     need one reformat  Example 2     Very short one       Needs no reformat  Example 3     Extremely long one   This description is long                                     multiple reformatted lines.    So, it loses the interior lines of a multiple reformat.  To get 
those I revisualized the structure of these lines thus:  \(.\{35}\)\(.\{,30}\)\( .\{,30}\)\+  and that all I really needed to do is replace that leading 
space in each of the repeated third fields with \r@@\1, ie 
that my first :s should be something like  :'a,'b-1s/.\{66,}/\=substitute(submatch(0),'\(.\{35}\)\(.\{,30}\)\( .\{,30}\)\+', "\=substitute(submatch(3), '^ ', '\r@@\1', '')", 'g')  which produced this output  =substitute(submatch(3), '^ ', '  @@ ', '')  Example 2     Very short one       Needs no reformat  =substitute(submatch(3), '^ ', '  @@ ', '')=substitute(submatch(3), '^ ', '  @@ ', '')  which I read as the second \=expression is not being treated 
as such, but no variations like doubling the \ to cater for 
the enclosing "s makes any difference. Advice as to how to 
proceed, please.  

--

Graham Lawrence

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