Re: Replacing a range of numbers

Thank you very much.

On Wed, Jun 22, 2011 at 02:24, Tim Chase <vim@tim.thechases.com> wrote:
> On 06/21/2011 04:45 PM, Grador wrote:
>>
>> Hi,
>> I have lines like this(there could be any number):
>> DELAY : 462
>>
>> I want to replace all lines with number higher then 200 with 200. So
>> the line above should looks like this:
>> DELAY : 200
>>
>> If I use this replace commnad:
>> :%s/DELAY : [201-9999]/DELAY : 200/g
>
> That's a character-class which would only match 1 digit.  I've suggested
> that Vim offer such a token, however nobody's taken me up on the
> proposition.  That said, for the general case, a bit of a hack can be done
> with something like
>
>  :%s/\(DELAY : \)\(\d\+\)/\=submatch(1).(submatch(2)>200?200:submatch(2))/g
>
> That said, for your particular case, you can use the regexp
>
>  :%s/DELAY : \zs[2-9]\d\{2}\|\d\{4,}/200/g
>
> which is more hard-coded to your values.
>
> -tim
>
>
>

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