Re: funcrefs forms

On Mon, Dec 30, 2013 at 10:18:21PM +0400, Nikolay Pavlov wrote:
> On Dec 30, 2013 5:58 PM, "Alexandre Hoïde" <alexandre.hoide@gmail.com>
> wrote:
> >
> > On Mon, Dec 30, 2013 at 08:55:17AM +0100, Alexandre Hoïde wrote:
> > > .vim <--
> > > function! s:SID()
> > > return matchstr(expand('<sfile>'), '<SNR>\zs\d\+\ze_SID$')
> > > endfunction
> > >
> > > function! s:objectConstructor(name)
> > > let obj = {}
> > > let obj.name = a:name
> > > let obj.form1 = s:objFuncs.form1
> > > let obj.form2 = function('<SNR>' . s:SID() . '_s:objFuncs_form2')
> > > return obj
> > > endfunction
> > >
> > > let s:objFuncs = {}
> > >
> > > function! s:objFuncs.form1()
> > > echo self.name
> > > endfunction
> > >
> > > function! <SID>s:objFuncs_form2() dict
> > > echo self.name
> > > endfunction
> > >
> > > let otst = s:objectConstructor('test')
> > > call otst.form1()
> > > call otst.form2()
> > > -->
> >
> > … to be more specific, on the sample code above, the following :
> > <--
> > echo function('s:objFuncs.form1')
>
> Now please try calling this (i.e. just append ()). *function() is not a
> replacement for eval*. You have found function() bug, nothing more. To get
> *real* results *echo actual funcref*. As I said if you define function
> inside a dictionary *you already get funcref*. Thus what you need is just
> echo s:objFuncs.form1.
>
Hi and thanks again for taking some time to help. Although I allready
knew how to get the *real* result… thanks to your answer to my first
thread.

Here, I did not put this "echo function('s:objFuncs.form1/2)" to get
the real result, but just to illustrate the fact that, to me, form1 and
form2 seems to be equivalent :
> > <SNR>36_objFuncs.form1
> > <SNR>36_s:objFuncs_form2

So I (still) wonder why some real developpers would use form2 (the non
anonymous version) rather than form1 ? I hope this claryfies my question
and that I understood your answer correctly. ^^

Best regards.

> > echo function('<SNR>' . s:SID() . '_s:objFuncs_form2')
> > --> Gives <--
> > <SNR>36_objFuncs.form1
> > <SNR>36_s:objFuncs_form2
> > -->
> >
> > Except form1 being {anonymous,numbered}-function and form2 beeing
> > just a dictionary-function, I don't see much difference between the 2
> > forms.
> >
> > The 1st form being more concise, I was wondering
> > a) why would someone use form2 (which I came accross on riml¹ README).
> > b) what makes the anonymous form1 preferable (besides conciseness)
> >
> > ¹ https://github.com/luke-gru/riml
> >

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