Re: why doesn't min take more than 1 parameter?

On 2021-01-02 06:47, L A Walsh wrote:
> trunc(min(3,1+log(1+line('$'))/log(10)))
>
> but I get E118: Too many arguments for function: min.

min() expects a single list-like argument so try

trunc(min([3,1+log(1+line('$'))/log(10)]))

which creates a list-literal with "3" as the first item and your 1+…
as the second element.

-tim



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