Re: why doesn't min take more than 1 parameter?

On 2021/01/02 06:57, Yongwei Wu wrote:
> Just do ":help min()", it will tell you:
>
> min({expr}) Return the minimum value of all items in {expr}.
> {expr} can be a |List| or a |Dictionary|.
>
> So the simplest solution seems to be:
>
> trunc(min([3, float2nr(1+log(1+line('$'))/log(10))]))
>
---
Thanks, when I typed ":help min()", I got
min({list}), and didn't know if the curly braces, "{}"
were needed, but never would have guess I needed
square brackets "[]".

I had 'trunc' to convert from float to a truncated
integer, but notice that you are using "float2nr".

Didn't know I would have needed that either (I had
used the output of 'printf' to go from a number to
a string.

Thanks for the hints and, especially, the example.

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