Re: pattern of func

Le mardi 20 février 2018 00:27:36 UTC+1, Arun E a écrit :
> That is due to the "greedy" nature of ".*". Replace ".*" with ".\{-}".
>
>
> Anycase, for a preview of what your pattern would match, you could 
> surround your expression of interest within \zs and \ze like
>    /^.*\zs\(\S\+()\)\ze
>
>
> If you have "incsearch" set, you could immediately see what your
> pattern matches.
>
>
> Regards,
> -Arun
>
>
> On Mon, Feb 19, 2018 at 12:40 PM, Ni Va <niva...@gmail.com> wrote:
> Hi,
>
>
>
> 1/Got a list mirror of file read that contains these kind of lines:
>
> 19 févr. 2018 15:49:09.301       Foo.BarFoo() - FIN TOTAL temps : 0,013ms
>
>
>
>
>
> 2/ attempt to map( the list and retrieve func and time
>
>
>
>   let patfunc = '\(\S\+()\)'
>
>   let pattime = '\(\d\+\,\d\+\)'
>
>   let linepat = '^.*'.patfunc.'.*'.pattime.'.*$'
>
>
>
>   let minitestlist = map(totaltimelist[0:10], 'substitute(v:val, linepat, "\\1 : \\2", "")')
>
>
>
>
>
>
>
> 3/ It results in
>
>
>
> ['o():0,013',....
>
>
>
> Why for the first backward ref I got only last char.
>
>
>
> Thank you
>
> Niva
>
>
>
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Thank you it works like that:

let patfunc = '\(\S\+()\)'
let pattime = '\(\d\+\,\d\+\)'

let linepat = '^.\{-}'.patfunc.'.*'.pattime.'.\{-}$'
let minitestlist = map(copy(totaltimelist)[0:10], 'substitute(v:val, linepat, "\\1 : \\2", "")')

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