With a sample script line like the following:
printf "A(%14s), B(%s), C(%14s), D(%14s), E(%14s), F(%3s), G(%-24s), H(%4s), I(%14s), J(%s),", "${x01}","${x02}","${x03}","${x04}","${x05}","${x06}","${x07}","${x08}","${x09}","${x10}"
With my cursor at "B" how can I delete from the current cursor position (col 18) to the first double-quote mark (") efficiently?
Thank you.
-- --
You received this message from the "vim_use" maillist.
Do not top-post! Type your reply below the text you are replying to.
For more information, visit http://www.vim.org/maillist.php
---
You received this message because you are subscribed to the Google Groups "vim_use" group.
To unsubscribe from this group and stop receiving emails from it, send an email to vim_use+unsubscribe@googlegroups.com.
To view this discussion on the web visit https://groups.google.com/d/msgid/vim_use/c8220bfd-cad2-4365-8c74-5826488d110dn%40googlegroups.com.
No comments:
Post a Comment