Re: vim function problem w/numeric arguments

On Tue, Jan 5, 2016 at 7:28 PM, JomarBueyes <jomarbueyes@hotmail.com> wrote:
> Hi,
>
> I'm having this problem: I define a function as
>
> function SetTabs(w)
> set sw=a:w
> set tabstop=a:w
> ( some other settings )
> endfunction
>
> When I try to use the function as:
>
> call SetTabs(4)
>
> I get an error on the first line:
> Number required after =: sw=a:w
>
> I tried coercing a:w into a number 'width' that I then try to use to
> set sw=width
> These are some of the ways I tried that did not work:
> let width = str2nr(a:w)
> let width = str2nr(a:w)*1
> let width = str2nr(a:w)*1.0
> also tried dividing instead of multiplying and adding or subtracting 0 or 0.0.
>
> I tried to convert in two steps such as:
> let width = str2nr(a:w)+1
> let width -= 1
> I tried changing 1 to 1.0, I tried first subtracting, then adding.
>
> Neither attempt has worked.
>
> Any pointer to what I'm doing wrong will be greatly appreciated.
> (I'm using vim 4.3 on either bash or tcsh under Mac OS 10.7.5).
>
> Thank you in advance,
>
> Jomar
>
> PS: My idea for this function is to quickly change sw and tabstop when I'm editing files from colleagues, some of which use sw=2, some sw=3, some sw=4.


What you're doing wrong is that you are using the _name_ of a variable
as argument to the :set command; it expects the _value_ to be given
the option.

You should use either
let &sw = a:w
or
exe "set sw=" . a:w

See
:help :let-&
:help :execute

Best regards,
Tony.

--
--
You received this message from the "vim_use" maillist.
Do not top-post! Type your reply below the text you are replying to.
For more information, visit http://www.vim.org/maillist.php

---
You received this message because you are subscribed to the Google Groups "vim_use" group.
To unsubscribe from this group and stop receiving emails from it, send an email to vim_use+unsubscribe@googlegroups.com.
For more options, visit https://groups.google.com/d/optout.