Re: decrease number?

Thanks Tim,

Johns did work exactly the way I wanted it to.

I like yours too.

On Mon, Jun 19, 2017 at 8:37 PM, Tim Chase <vim@tim.thechases.com> wrote:

On 2017-06-19 22:29, John Passaro wrote:
> use the expression register:
>
> s/\v\w+\="\zs\d\d+\ze"/\=submatch(0)-10/g

Beware that this catches any variable name (not just [xy][12] which
may or may not be what you want), and also doesn't catch
negative-number values.

But for the general case of the example you (OP) gave, John's works
well too.

-tim

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