Re: replace submatches in matchlist

2014. október 22., szerda 17:44:10 UTC+2 időpontban Christian Brabandt a következőt írta:
> On Mi, 22 Okt 2014, BimbaLaszlo wrote:
>
>
>
> > Is there a good way to replace submatches in matchlist() and modify the
>
> > original line with it? I like to write a script which modifies all of the
>
> > submatches in a pattern in one step.
>
> >
>
> > For example the original line is 'some AfooBar' and i like to change it to
>
> > 'some CfooDar':
>
> >
>
> > let pattern = '\(A\)foo\(B\)'
>
> > let line = 'some AfooBar'
>
> > let found = matchlist( line, pattern )
>
> >
>
> > The 'found' contains "['AfooB', 'A', 'B', '', '', '', '', '', '', '']". Now i
>
> > like to modify the 'line' to 'some CfooDar' so the best should be:
>
> >
>
> > let found[1] = 'C'
>
> > let found[3] = 'D'
>
> > let line = MATCHLIST_TO_STRING( found )
>
> >
>
> > As i know it's not possible with the builtin functions, so i need to write
>
> > one. The beginning of the line is not modified till the match, thus i can copy
>
> > that part to the 'new_line':
>
> >
>
> > let new_line = strpart( line, 0, match( line, pattern ) )
>
> >
>
> > But at this point i don't know how to continue. I can append the modified 'A'
>
> > immediately, because the pattern starts with it (in this example, but the user
>
> > can use any kind of pattern). But how can i find out the (offset) index of the
>
> > 'foo' and the 'B'? In this example it's trivial, because there is no other
>
> > 'foo' and 'B' in the line, but let see another example:
>
> >
>
> > let line = 'A A A A A'
>
> > let pattern = 'A \(A\) A \(A\)'
>
> >
>
> > If i like to modify this to 'A B A C A' then it's hard to detect the position
>
> > of the submatches in the 'line'.
>
> >
>
> > One solution is to use submatches for the 'inner words' (like 'foo' in the
>
> > previous example'), but it decreasing the number of useful submatches. For
>
> > example:
>
> >
>
> > let pattern = '\(A\)\(foo\)\(B\)'
>
> > let line = 'some AfooBar'
>
> > let found = matchlist( line, pattern )
>
> > " Remove the full match, we need only the submatches.
>
> > call remove( found, 0 )
>
> > let found[0] = 'C'
>
> > let found[2] = 'D'
>
> > let new_line = strpart( line, 0, match( line, pattern ) ) . join( found, '')
>
> >
>
> > In this case we used one additional submatch, but the 'A \(A\) A \(A\) A' may
>
> > become '\(A \)\(A\)\( A \)\(A\)\( A\)' and it's too lot.
>
> >
>
> > So is there a good way to replace all of the submatches with a new value in
>
> > one step?
>
>
>
> Isn't that what you would use submatch() in the replacement part of a :s
>
> command (mentioned in :h sub-replace-expression).
>
>
>
> Best,
>
> Christian

I don't understand what do you like to tell me... o_O The matchlist() gives me all of the submatches, but i like to modify the values of those, then "compile" the original line again.

* Get the submatches from line ('some AfooBar' -> 'A', 'B'),
* modify those ('A' -> 'C', 'B' -> '),
* 'compile' the original line. ('some CfooDar'

--
--
You received this message from the "vim_use" maillist.
Do not top-post! Type your reply below the text you are replying to.
For more information, visit http://www.vim.org/maillist.php

---
You received this message because you are subscribed to the Google Groups "vim_use" group.
To unsubscribe from this group and stop receiving emails from it, send an email to vim_use+unsubscribe@googlegroups.com.
For more options, visit https://groups.google.com/d/optout.