Re: Expanding a variable

On Wed, Dec 3, 2014 at 12:23 AM, John Beckett <johnb.beckett@gmail.com> wrote:

David Fishburn wrote:
> Assume the net result is I have this:
> let test_newline = '\n'

Is this what you mean?

    :let x = '\n'
    :let x = substitute(x, '\\n', '\n', 'g')
    :echo char2nr(x)

Thanks for the response John.

 

The first line puts a string of two characters (a backslash and "n") into x.

I am glad you mentioned this because I was thinking this was 1 character (knowing what I wanted), but as you correctly pointed out, it is 2 characters.

So I was very close in my examples:

echo substitute(test_newline, '\\', "\\\\", 'g')

Had I extended that to include the 'n', it worked as I expected:

echo substitute(test_newline, '\\n', "\n", 'g')

This shows the blank lines being echoed.

Much appreciated.

Dave

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