Re: Submatch and regex replace

On Fri, Oct 25, 2013 at 6:01 PM, Paul Isambert <zappathustra@free.fr> wrote:

stosss <stosss@gmail.com> a écrit:

> Starting out with a number at the beginning of the line and want to change
> it from a single or double digit to a triple digit such as 1 to 001 or 10
> to 010 and 100 stays as is
>
> :%s@\(\d\+\)@\=printf("%03d", submatch(1))@
>
> I also want to add some more information around it such as
>
> :%s@\(\d\+\)@<span="b001c001v\1">\1</span>
>
> It would be better to be able to do it in one pass so that I end up going
> from
>
> 1
>
> to
>
> <span="b001c001v001">1</span>
>
> I can do my second :s first and then do my first :s second.
>
> Can I do this all in one pass? I haven't been able to figure out how to do
> what I want using the submatch example above and get the final result that
> I want.

Why not simply combine the two?

    :%s@\d\+@\='<span="b001c001v' . printf("%03d", submatch(0)) . '">' . submatch(0) . '</span>'

Not the nicest line in the world, but it should work (note that I've
removed submatches to save a few characters).

Best,
Paul

Excellent! Combining is what I was wanting. Thank you for showing me that.

Jack

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