> On 2/04/11 12:57 PM, Spiros Bousbouras wrote:
>
>
>
> > The following on GNU/Linux with vim version 7.1
>
> > prompt> cat myscript
> > #!/bin/sh
> > echo 1
>
> > prompt> cat myscript.vim
> > function! Check()
> > let l:r = system("./myscript")
> > if l:r == "1"
> > echo "Good"
> > else
> > echo "Length of l:r is" strlen(l:r)
> > echoerr "l:r is" l:r
> > endif
> > endfunction
>
> > I start a vim session and do
>
> > :source myscript.vim
> > :echo Check()
>
> > and get
>
> > Length of l:r is 2
> > Error detected while processing function Check:
> > line 6:
> > l:r is 1^@
> > 0
>
> > Replacing inside Check()
> > if l:r == "1"
> > with
> > if l:r == "1\000"
> > doesn't make any difference.
>
> Try
>
> if l:r == "1\n"
Yes , that works , thank you.
> I think it's :echoerr that is not displaying the \n in the string
> correctly, but interpreting it as if it were \n in a buffer (which
> stands in place of \0). If you just used :echo you would see 1 followed
> by a blank line.
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