Re: Substitute via expression on matched text

Hi,

You can use submatch(<number>).

In your example:

:%s/\(PP \d\+,\)\(\d\+\)/\=submatch(1).(submatch(2)-120)/

submatch(0) will contain whole string like &.

Thanks

Venu

On Tue, Apr 5, 2011 at 12:28 AM, Taylor Hedberg <tmhedberg@gmail.com> wrote:

I have a file that contains several lines that start out similar to
these:

       PP 124,152
       PP 83,938
       PP 877,994

In other words, these lines match the regex:

       /^PP \d\+,\d\+/

I wanted to decrement the second number in each pair by 120, and I ended
up with something like this:

       :g/^PP /norm! f,l120^X

where the "^X" is a literal C-x character.

This worked just fine, but I wondered if there was a way to do the same
thing with a substitute command instead of a global. I tried this:

       :%s/^PP \d\+,\zs\d\+/\=\& - 120/

but it didn't work, nor did I really expect it to. The "\&",
representing the current matched text, is not valid within an
expression.

So my question is, how can I write a replacement expression for a
substitute command that performs some operation (such as arithmetic) on
the matched text itself? Is there a special register that holds the
current match?

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