Re: Measuring lines

On 2013-06-09 20:37, meino.cramer@gmx.de wrote:
> Paul Isambert <zappathustra@free.fr> [13-06-09 20:28]:
> > I'm not sure I understand you correctly, but perhaps the following
>> will help:
>>
>> function! s:bars ()
[snip]
>> endfunction
>> com! -buffer Bars call s:bars()
>>
>> | | | | abcde | |
>> produces:
>> | | | | abcde | |
>> 0 12 3 10 7 1
>
> yes,yes,yes,!!! Exactly what I want! THANKS A LOT! You helped me
> more as you may think :) ! Great help! 8)
...
>> (I'm sure there's a Vim wizard out there who can do all that with
>> only ":substitute".)

Though just a first pass, since Paul threw down the challenge:

:s/.*/\=submatch(0)."\n".(join(map(split(submatch(0), '|', 1),
'printf("%".strlen(v:val)."s", strlen(v:val))')))/g

gives a pretty close approximation to his solution as a
one-line :substitute command. Differences I notice:

1) it has one extra 0-width field listed at the end which shows the
width of the last column (in Paul's sample input, it was zero-width,
but if there were additional characters, it would list how wide the
field was)

2) it right-justifies the number with the pipe rather than
left-justifying it.

So on Paul's example, I get

| | | | abcde | |
0 12 3 10 7 1 0

-tim



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