Re: Match all characters enclosed in brackets

On 2013-08-09 00:46, rameo wrote:
> I have trouble finding the correct regex.
>
> I know that a sequence of characters enclosed in brackets means
> their optional: [xyz] means any 'x' OR 'y' OR 'z'
>
> but how can I find them all?
> any 'x' AND 'y' AND 'z' in whatever sequence and quantity

Because the syntax "[xyz]" means "'x' at this location or 'y' at this
location or 'z' at this location", using AND would automatically fail
for this context. Only one character can be at a given place in the
text.

If you want them in sequence, then you want "x.*y.*z" which means any
'x' followed eventually by a 'y', followed eventually by a 'z'

If you want to assert that all 3 exist on the same line but in any
order, that's a bit uglier, but made easier by Dr. Chip's logipat.vim
plugin. Using that suggests

\%(.*x.*\&\%(.*y.*\&.*z.*\)\)

where the "\&" atom asserts that each of the pattern parts have to
match.

-tim


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