> I want to do :%s@\(<br />\)\(1\)@\1<linebreak>\2@
>
> and have it find <br />1 and return:
>
> <br />
> 1
I'm not sure what "return" means, but the following will change
each "<br />1" by inserting a newline before the "1".
:%s@\(<br />\)\(1\)@\1\r\2@g
I would be inclined to replace "<br />" with "<br\s*/>".
John
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