Re: How to use %03d on existing data

Things for the help! And thanks for telling me where I can find more
information about it. Your first example actually works for me because
the leading 0s aren't in the beginning.

This helps cut out a step.

Cheers,
Jack

On Wed, Oct 17, 2012 at 10:32 PM, Benjamin R. Haskell <vim@benizi.com> wrote:
> On Wed, 17 Oct 2012, stosss wrote:
>
>> Okay I have something that should be achievable but I can't figure it out.
>> I have a lot of files with data for books. Each file is a book and is in
>> chapters with lines of text.
>>
>> sample of existing data:
>>
>> <h2>1</h2><p>
>> 1 line of text.<br>
>> 2 another line of text.<br>
>> 3 lines of text.<br>
>> ...
>> 10 More lines of text.<br>
>> ...
>> 100 Even more lines of text.<br>
>>
>> [...]
>>
>>
>> What I want is:
>>
>> <h2 id="b001c001">1</h2><p>
>> <span id="b001c001v001">1</span> line of text.<br />
>> <span id="b001c001v002">2</span> another line of text.<br />
>> <span id="b001c001v003">3</span> lines of text.<br />
>> ...
>> <span id="b001c001v010">10</span> More lines of text.<br />
>> ...
>> <span id="b001c001v100">100</span> Even more lines of text.
>>
>> [...]
>>
>>
>> I can't figure out how to use %03d to change my numbers from 1 to 001 I
>> also would like to figure out how to use setreg() to increase this c001 part
>> of the id label so it changes to c002 when it is supposed to so I don't have
>> to reset my map at every chapter. I need to figure out the first part before
>> I figure out the second part. The examples in the VIM tips aren't helping me
>> figure this out. Maybe I am looking in the wrong place.
>>
>> I tried all sorts of things but nothing worked. I don't remember all the
>> things I tried but here are a few attempts I made that didn't work:
>>
>> :%s@\([0-9]\+\)@%03d\1@
>> :%s@\([0-9]\+\)@\=printf("%03d"\1)@
>> :%s@\([0-9]\+\)@\=printf("%03d\1")@
>>
>> I don't understand how to use that number format in my search and replace.
>> The examples on the pages linked above don't give me any clues. It has been
>> a very long time since I have asked for help with VIM. I usually have been
>> able to find answers in the tips. But not this time.
>
>
>
> For the %03d part:
>
> :%s@\(\d\+\)@\=printf("%03d", submatch(1))@g
>
> See:
> :help submatch()
>
> But, that treats numbers that look like octal incorrectly:
>
> E.g.:
> abc010def -> abc008def
> (because 010-base-8 is 8-base-10.)
>
> So consume the zeros ahead of time:
> :%s@0\*\(\d\+\)@\=printf("%03d", submatch(1))@g
>
> --
> Best,
> Ben
>
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