Re: [Rephrased] Problem with a regular expression in Vim

On Wed, Oct 03, 2012 at 11:37:36AM EDT, Ben Fritz wrote:

[..]

> This seems to work for me:
>
> \%(^\|[^=]*==[^=]*==\)\@<=[^=]*==\zs[^=]*\ze==

> Probably this pattern could be made simpler..

Maybe something like this..?

| \(^[^=]*\|==[^=]*\)==\zs[^=]*

Only briefly tested since I felt the solution to what is after all
a trivial problem shouldn't be that complicated in the first place.

I researched it a little further over the weekend, and eventually, I ran
into this via a perl forum:

| % echo 'ascii string: "string1", unicode string: "κορδόνι"' | perl -wnE 'say for /"[^"]*"/g
| "string1"
| "κορδόνι"

I don't know perl, but it looks like the match on the two sample strings
includes the quotes.

Now, if you add a capturing group¹ around the [^"]* negated character
class that matches the actual strings, this is what you get:

| % echo 'ascii string: "string1", unicode string: "κορδόνι"' | perl -wnE 'say for /"([^"]*)"/g
| string1
| κορδόνι

This time the match does _not_ include the quotes.

Or, with our sample text:

| % echo 'xxx==aaa==bbbccc==ddd==yyy' | perl -wnE 'say for /==[^=]*==/g'
| ==aaa==
| ==ddd==
|
| % echo 'xxx==aaa==bbbccc==ddd==yyy' | perl -wnE 'say for /==([^=]*)==/g'
| aaa
| ddd

So, I tried the same approach with Vim:

| xxx==aaa==bbbccc==ddd==yyy
|
| /==[^=]*==
| /==\([^=]*\)==

But it doesn't make any difference..

Both regexes match '==aaa==' and '==ddd==' including the quotes.

Isn't Vim supposed to mimic perl regexes..?

Or is there something in Vim's regex syntax that would make it work?

CJ

¹ 'sub-expression' in Vim parlance..?

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