Sunday, August 11, 2013

Re: vim: how to use back reference to compare strings?

On Sunday, August 11, 2013 2:44:28 PM UTC+12, ping wrote:
> any idea of what I missed here?

With

:g#\(abc\d\+\)\(.*\)\(abc\d\+\)\(.*\)#s//\=Diff(submatch(1),submatch(2))/n

I get all lines reporting a difference, changing the echo to

echo "found a diff!" a:a a:b

shows me why.

Back references are numbered from the left, by their opening \(. Your pattern is

\(abc\d\+\)\(.*\)\(abc\d\+\)\(.*\)

where you've bracketed the middle bit, so that's returned by submatch(2); you want to compare matches 1 and 3. Using

:g#\(abc\d\+\)\(.*\)\(abc\d\+\)\(.*\)#s//\=Diff(submatch(1),submatch(3))/n

I get

found a diff! abc123 abc1234
found a diff! abc123 abc1234
5 substitutions on 5 lines

It's an ugly hack, any way. I've just noticed that the matchlist() function gives access to submatches, a function using that would be cleaner:

func! Diff2(pat)
call setpos('.',[0, 1, 1, 0]) " go to beginning
while search(a:pat, 'W')
let l = matchlist(getline('.'),a:pat)
if len(l) >= 4 && l[1] != l[3]
echo 'found a diff:' l[1] l[3]
endif
endwhile
endfunc

:call Diff2('\(abc\d\+\)\(.*\)\(abc\d\+\)\(.*\)')

Regards, John Little

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