Re: vim: how to use back reference to compare strings?

I also checked "help \@!", and got this:

Useful example: to find "foo" in a line that does not contain "bar":
/^\%(.*bar\)\@!.*\zsfoo

but it seems, it desn't work with back-ref ...

guys, who can help explaining these ?

On Sat, Aug 10, 2013 at 10:50 PM, ping song <songpingemail@gmail.com> wrote:

hi: 

thanks for the response, this look much shorter!

but this doesn't work either...

:g/\(abc\d\+\).*\1\@!\(.*\)
1 abc123 bla bla bla abc123 bla bla
2 abc123 bla bla bla abc1234 bla bla
3 abc123 bla bla bla abc123 bla bla
4 abc123 bla bla bla abc1234 bla bla
5 abc123 bla bla bla abc123 bla bla

I'm expecting to see only line 2&4...

any idea?

regards

ping

On Sat, Aug 10, 2013 at 5:11 PM, Niklas Reinhart <niklas.reinhart@gmail.com> wrote:

Hi,

this works for me:

        abc\(\d\+\).*abc\1\@!

Regards

Niklas


Am Sat, 10 Aug 2013 16:45:30 -0400
schrieb Ping Song <songpingemail@gmail.com>:

> thanks. yes I know we can use that way(/1 /2 ..etc).
> what I meant is, how to use these to actually do the compare in a vim
> ex command line? sth like :
>
> :g#\(abc\d\+) bla bla \(abc\d\+\)#if /1 != /2 then echo "found a
> diff !"
>
> of course this doesn't work but just some fake code to clarify what I
> meant
>
>
>
> On Sat, Aug 10, 2013 at 3:30 AM, Marcin Szamotulski
> <mszamot@gmail.com> wrote: Hi,
>
> I am not sure if I understand you correctly but you can use \(...\)
> and and then reuse it with \1 (it matches the same string as what
> \(...\) have matched).
>
> Regards,
> Marcin
>
>
>
> On 00:44 Sat 10 Aug     , ping song wrote:
> > hi guys:
> > I run into a scenario that , I need to compare 2 part of the regex
> > string in one line :
> >
> > "abc123456 bla bla bla abc1234"
> >
> > so I'm thinking, can we use the backreference, to compare the first
> > abc\d\+ with the second one and only print out a message in case we
> > detect the different ones ? preferably if this can be done with one
> > command...
> >
> > thanks!
> >
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