Re: How to check for $ProgramFiles(x86) ?

On 10/25/2012 01:09 AM, George V. Reilly wrote:
> On Wed, Oct 24, 2012 at 2:50 PM, Ben Fritz <fritzophrenic@gmail.com> wrote:
>> On Wednesday, October 24, 2012 4:25:41 PM UTC-5, Gary Johnson wrote:
>>>
>>> I think the following or a variation should do it. I was only able
>>> to test it on names without parentheses as I didn't see any variable
>>> names with them in my environment.
>>>
>>> split(system('set ProgramFiles(x86)', '=')[1]
>>>
>>> gets the value and
>>>
>>> system('set ProgramFiles(x86)') =~ 'not defined'
>>>
>>> will evaluate to true if the variable is not defined.
>>>
>>
>> Not quite. You get hit by Windows *#$&#ing command-line quoting.
>>
>> This works for me:
>>
>> :echo system('set PROGRAMFILES^(x86^)')
>
> In the past, I've solved very similar problems with batch files [1]
> and Bash scripts [2].
> The parentheses in the environment variable name are asinine.
>
> [1] http://weblogs.asp.net/george_v_reilly/archive/2009/09/11/launching-32-bit-applications-from-batchfiles-on-win64.aspx
> @setlocal
> @set _pf=%ProgramFiles%
> @if not "[%ProgramFiles(x86)%]"=="[]" set _pf=%ProgramFiles(x86)%
> @start "" /b "%_pf%\SourceGear\DiffMerge\DiffMerge.exe" %*
>
> [2] http://thread.gmane.org/gmane.comp.gnu.mingw.user/31262/focus=31273
> #!/bin/sh
> pf=`env | sed -n s,'^PROGRAMFILES(X86)=',,p`
> if [ -z "$pf" ]; then pf="$PROGRAMFILES"; fi
> "$pf/SourceGear/DiffMerge/DiffMerge.exe" $*

Thank you for your answers. I think a simple
let l:pf = system('Echo %ProgramFiles(x86)%')
if l:pf == '%ProgramFiles(x86)%'
...
will work well enough.

Thank you,
Timothy Madden

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