Re: matchend() and \zs

On 07:04 Thu 19 Apr , rameo wrote:
> On Thursday, April 19, 2012 1:09:10 PM UTC+2, jott...@googlemail.com wrote:
> > Hi,
> >
> > rameo wrote:
> > > My file - first line:
> > > an 91.010 &System.-sep010- <Nop>
> > >
> > > I want to copy all numbers after -sep
> > > echo match(getline(1), 'sep\zs\d\+\ze-')
> > > gives 23 as output.
> > > All ok.
> > >
> > > but
> > > echo matchend(getline(1), 'sep\zs\d\+\ze-', 23)
> > > gives -1 as output.
> > > Why?
> >
> > because the 23 that was returned from match() is the position of the
> > first digit, not the position of 'sep'. Thus you try to find
> > 'sep\zs\d\+\ze-' in a string that for matchend() seems to consist only
> > of
> >
> > 010- <Nop>
> >
> >
> > Regards,
> > J�rgen
> >
> > --
> > Sometimes I think the surest sign that intelligent life exists elsewhere
> > in the universe is that none of it has tried to contact us. (Calvin)
>
> Thanks Jurgen,
>
> I use match() and matchend() to copy search matches to the clipboard
> or remove them out of the text.
>
> What can I do to make match() and matchend() work in order to copy p.e. the numbers after -sep?
>
> Regards,
> Raimond
>
> --
> You received this message from the "vim_use" maillist.
> Do not top-post! Type your reply below the text you are replying to.
> For more information, visit http://www.vim.org/maillist.php

It seems that
echo matchend(getline(1), '\d\+\ze-', 23)
should work just fine, where 23 is obtained by
match(getline(1), 'sep\zs\s\+\ze-')
You do not need to match sep twice.

Best,
Marcin

--
You received this message from the "vim_use" maillist.
Do not top-post! Type your reply below the text you are replying to.
For more information, visit http://www.vim.org/maillist.php