Re: Why matchstr returns also text matched by zero-width pattern?

On Tuesday, September 18, 2012 10:02:32 AM UTC-5, Ben Fritz wrote:
> On Monday, September 17, 2012 12:07:58 PM UTC-5, Martin Jiricka wrote:
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> > Hello!
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> > First of all, thank you for your reply!
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> > > I think you wanted one of these:
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> > > \v(123)@<=abc
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> > Yes, this is what I wanted.
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> > > Additionally, if this WERE working as you expect, your pattern would NEVER
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> > > match. You are saying,
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> > > "match abc where 123 also matches in the same position"
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> > > which cannot possibly succeed, because 123 does not match where abc matches.
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> > I don't get this. Of course I didn't want to match 'abc' on '123'. (That's the purpose of regexes, match pattern where the pattern match, I would say...?) I posted simplified example, originally I wanted to match last word before the parenthesis, which is a function name. The '@<=' works fine for this.
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> Yes, and @<= is what you wanted. You used @=, which is a zero-width look-ahead, not a look-behind.
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> E.g. /\(abc\)\@=\a\+ will match the whole string "abcdefghij"; it says "find a string of alphabetic characters starting with 'abc'". /\(abc\)\@<=\a\+ will match the "defghij" in "abcdefghij" only; it says, "find a string of alphabetic characters preceded by 'abc'".

Incidentally, I cannot recall ever having a use for \@=. As the help says, it does the same thing as \&.

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