Re: trouble with pattern, character collections

Hi Marc!

On Mo, 18 Feb 2013, Marc Weber wrote:

> I don't think that additional threads are going to help
> There is an issue, and we should find a way to fix (IMHO).
> Let me summarize again - and tell me if you feel differently.
>
> Test cases:
> [1] echo len(matchstr("\n",'\zs[^\n]\ze'))
> [2] echo len(matchstr("\n","\\zs[^\n]\\ze"))
>
> I expect both do the same, the difference is that the second as chr(10) in [^],
> while the first has \n (which should be translated to chr(10).
>
> However I obsorve that [2] returns 0 as expected , but [1] does return
> 1, thus it matches \n even though I told Vim that I do not want to match
> it. People told me this was because '.' is equal to [^\n].

No, it is because "\n" is evaluated to a true line feed, so "[^\n]"
matches anything but ASCII NUL and ASCII 10, while '[^\n]' matches
anything but ASCII NUL (which is used internally by Vim to distinguish
lines from each other (e.g. a line seperator), so that a . matches
anyhing in the buffer but the line seperator)

> If so which is the best way to fix this - and which should be the way to
> express [^\n] meaning do not match \n rather than behave like '.' then ?

[^\n] should always behave like '.'

Mit freundlichen Grüßen
Christian
--
Letzte Worte eines Machos:
"Hallo Süße, wie wär's mit uns beiden?"

--
--
You received this message from the "vim_use" maillist.
Do not top-post! Type your reply below the text you are replying to.
For more information, visit http://www.vim.org/maillist.php

---
You received this message because you are subscribed to the Google Groups "vim_use" group.
To unsubscribe from this group and stop receiving emails from it, send an email to vim_use+unsubscribe@googlegroups.com.
For more options, visit https://groups.google.com/groups/opt_out.