Re: How calling function from filter(dictionary)?

John Tobin wrote:

> On 26 January 2011 13:51, sgp <acs322000@yahoo.com> wrote:
>
>> How can I call a function from filter(dictionary)?
>>
>> This calls Compare() which then complains about val and tgt being
>> undefined
>>
>> let dic=filter(copy(self),'v:key =~ "^pre" ?0 :
>> call("Compare",[v:val, "'.tgt.'"])')
>> function! LXcompare(val,tgt) " val can be string or List
>> echo tgt
>
> echo val
>>
>
> You need to use a:tgt and a:val. See :help a:var for details.
>
>
>> return 0
>> endfunction
>>
>> TIA
>>
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Sorry, I'm the OP and gave an incomplete example. Below is a better example, which should filter a
dict by item value. A dict item value can be either a single string or a list of strings. Return 1 when the
single string or one of the list item strings matches argument tgt.

Two questions:
1. Why does Compare() stop on error (case dC) in spite of the catch statement?
2. How can I test the type of tgt without resorting to catch? I just want to tell a string from a List.

let d1 = {1:'A', 2:['B','C']}
function! Compare(val,tgt)
let re='^'.a:tgt.'$'
try | return a:val =~? re " a:val is a string
catch
"catch /^Vim\%((\a\+)\)\=:E691/ " catch Can only compare List with List
for v in a:val
if v =~? re | return 1 | endif
endfor
endtry
return 0
endfunction
let dA = {1:'A'}
echo filter(copy(dA),'call("Compare",[v:val, "A"])')
let dC = {1:'A', 2:['B','C']}
" should echo {2:['B','C']} but it stops on error, why?
echo filter(copy(dC),'call("Compare",[v:val, "C"])')

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